#1
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Why are the frets on a guitar not evenly spaced?
Sorry if this is a silly question - but would this not make it easier to play? or is there some kind of physical law that makes it impossible?
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#2
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Physics.
If the frets were equally spaced, the notes wouldn't be the ones in our 12-note scale. |
#3
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The frets are located so that they correspond to the locations where the strings will be in tune when pressed against them. If they were spaced at equal intervals, fretting consecutive frets would give you notes that were out of tune.
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Bob DeVellis |
#4
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Because for a string instrument, notes have a multiplicative, not an additive relationship...
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Emerald X20 Emerald X20-12 Fender Robert Cray Stratocaster Martin D18 Ambertone Martin 000-15sm |
#5
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Great question. They are not evenly spaced (for reasons already "noted"), but they are very precisely calculated and spaced mathematically. It's not for aesthetic purposes. Quote:
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#6
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Quote:
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PS. I love guitars! |
#7
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The middle of the crown.
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Derek Coombs Youtube -> Website -> Music -> Tabs Guitars by Mark Blanchard, Albert&Mueller, Paul Woolson, Collings, Composite Acoustics, and Derek Coombs "Reality is that which when you stop believing in it, doesn't go away." Woods hands pick by eye and ear
Made to one with pride and love To be that we hold so dear A voice from heavens above |
#8
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PS. I love guitars! |
#9
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#10
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"Music is much too important to be left to professionals." |
#11
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Simple really. This is a microtonal neck. Standard guitar necks are for the traditional western scale of twelve half-steps or semi-tones per octave. Those extra frets give you notes in between those twelve half steps. Micro tonal music is typically of Asian, Indian, or African origins.
You can get the in-between notes on any guitar using a slide, or by bending. The extra frets let you get there more precisely and reliably. |
#12
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Quote:
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#13
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Not that we needed a reason in the first place ...
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I wish I was nearly as good as my guitars are: 1977 Alvarez Yairi DY 57 / 2002 Martin DC-1E/ 2010 The Loar LH-700-VS/ 2012 Taylor Mini GS / 2015 Taylor 150e / 2015 Taylor 324ce SEB / 2018 Taylor 214e DLX / 2020 Taylor AD12e / 2021 Gibson J-185ce / 2022 Martin 000-15M ... and some electrics and such. |
#14
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Calculating fret distances. If you divide any scale length by the constant 17.817, you will get the distance from the front edge of the nut to the first fret. Here is one example: a scale length of 25.5" (650mm) divided by 17.817 gives 1.4312173" (36.482011mm), which can be rounded down to 1.431" (36.48mm). Well I was going to paste it here but it was too jumbled. You can read it here: https://educationcloset.com/2017/05/...-nothing-fret/ |
#15
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To be even more precise, in order for music to be easily transposed, the modern tempered scale was invented. In order to match it closely to the natural scale of 7 notes, 5 notes were introduced (sharps and flats) so that the ratio between each successive notes was fixed. Mathematically, to form the octave, the ratio between two successive notes has to be 2^(1/12) (2^12/12 = 2, which is the octave). This is pretty close to the natural scale. For instance, a perfect fifth in the natural scale is a ratio of 3/2 = 1.50, where in the tempered scale, it's 2^(7/12) = 1.498. So, this is the reason why the tempered scale is a compromise, and notes always sound a bit "off' on any instrument which uses the tempered scale.
Now, from physics, the fundamental frequency of a string (for the same string) is a constant divided by the vibrating length of the string: f = c/L. Hence, the ratio of the frequency of f1 and the next note, f2, is: f2/f1 = L2/L1 Which must equal 2^(1/12): L2/L1 = 2^(1/12) So, L2 = L1 2^(1/12) Hence, every successive note must 2^(1/12) closer to the nut as the previous fret.
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