#1
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Curious Breedlove question
Ok,so I bought a first year model Breedlove USA series concert which I love. It has a 3.75” soundhole and the larger concerto model does too. Now the second year version of my concert has a 4” hole yet the larger concerto still has 3.75”. Frankly I wouldn’t change a thing on mine,just curious. When I asked Breedlove in an email they just said is was due to the always evolving “sound optimization” process. Any thoughts? I would understand it more if the changes were reversed on the models. I know I’m going to get replies saying “just play the thing”
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Taylor 322,512ce 12 fret cedar/hog & 362ce Martin 00015SM Guild 1966 F20 Larrivee P03 sitka/hog,simple 6 OM & OM 09 Eastman E100ss-sb Gibson J185 & 2016 J35 Fender player plus telecaster & Mustang P90 Gretsch MIK 5622T Last edited by Lillis; 08-11-2019 at 09:24 PM. |
#2
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This thread is worthless without pics.
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Larrivee OM-03RE; O-01 Martin D-35; Guild F-212; Tacoma Roadking Breedlove American Series C20/SR Rainsong SFTA-FLE; WS3000; CH-PA Taylor GA3-12, Guild F-212 https://markhorning.bandcamp.com/music |
#3
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My guess is that the smaller body benefits from a larger sound hole more than the larger body does.
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#4
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I think it's the same reasoning behind Taylor's GS Mini models.. the larger sound hole helps create and project a larger, fuller sound than similar body styles of the same size.
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-Mike ____________________________________
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#5
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Bliss is owning a Breedlove about which one has no idea as to the soundhole size.
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1 dreadnought, 1 auditorium, 1 concert, and 2 travel guitars. |
#6
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I think that there was a Music Villa video recently that interviewed someone from Breedlove and they explained their process of optimizing the tone by narrowing down to 3 body shapes/sizes and then tweaking other things to get what they are looking for from each. I'm not sure if it will shed more light or not, but maybe.
Best, Jayne |